Question

The following query looks the table ids and return the id if for example 204720966837 is found.

My question is how can I do the opposite? I want to display the ids of those id that are not found.

SELECT id FROM ids WHERE id IN  ('204720966837', '163700377960', '24583115900', '1081617368').

For now I have 204720966837 saved in ids and this is what it prints. My goal is to print 163700377960, 24583115900, 1081617368

while($assoc = mysql_fetch_assoc($query)) {
    echo $assoc['id'];   
}

I have tried NOT IN but I get a zero return.

Answer 1

You could use a temporary table:

CREATE TEMPORARY TABLE temp_table (id int);

INSERT INTO temp_table(id) VALUES('204720966837'), ('163700377960'), ('24583115900'), ('1081617368');

SELECT id FROM temp_table WHERE id NOT IN(SELECT id FROM ids)

DROP TABLE temp_table;