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Home/ Questions/Q 8139163
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T11:44:03+00:00 2026-06-06T11:44:03+00:00

The following script is returning false, when I think that it should be returning

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The following script is returning false, when I think that it should be returning true. Any idea what is going on here? Thanks so much, guys!

test=['Pop']
test1='Pop'

if (test==('POP' or 'Pop' or 'pop' or ['POP'] or ['Pop'] or ['pop'])):    
    print "yes"
else:
    print "no"

Currently, the output is, ‘no’.

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  1. Editorial Team
    Editorial Team
    2026-06-06T11:44:05+00:00Added an answer on June 6, 2026 at 11:44 am

    You aren’t understanding how python processes the statement. Python isn’t natural language.

    if (test==(['Pop'] or 'Pop')):
    

    Because the or is inside the parens, it processes it first. So it looks at

    ['Pop'] or 'Pop'
    

    Since [‘Pop’] is considered True, python reduces the whole statement to:

    if (test==['Pop']):
    

    At this point, it tests whether test is equal to ['Pop']

    What you are actually wanting to do is:

    (test == ['Pop']) or (test == 'Pop')
    

    This is completely different than

     test == (['Pop'] or 'Pop')
    
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