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Home/ Questions/Q 7939417
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T23:05:33+00:00 2026-06-03T23:05:33+00:00

The following script produces a local variable ‘var’ referenced before assignment error: def func1():

  • 0

The following script produces a “local variable ‘var’ referenced before assignment” error:

def func1():
    var = var + 1

var = 1

func1()

How would you suggest to correct the code? Why does this error occur when the variable is declared in the script before the function is called?

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  1. Editorial Team
    Editorial Team
    2026-06-03T23:05:34+00:00Added an answer on June 3, 2026 at 11:05 pm

    You can use a global variable in other functions by declaring it as global in each function that modifies it:

    >>> var = 2
    >>> def func():
    ...     global var
    ...     var = var+1
    ...     return var
    ... 
    >>> func()
    3
    

    After OP edited question:
    If you are moving the variable after you define the function you will need to pass it to the function as a parameter.

    >>> def func(var):
    ...     var = var+1
    ...     return var
    ... 
    >>> var = 2
    >>> func(var)
    3
    
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