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Home/ Questions/Q 6568275
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T14:27:25+00:00 2026-05-25T14:27:25+00:00

the following script seems to work only in Safari function getPictures() { $.ajax({ type:

  • 0

the following script seems to work only in Safari

function getPictures() {
    $.ajax({
            type: "GET",
            url: "getimages.php",
            dataType: "xml",
            success: function(xml) {
                alert('success');
            }

    });
}

getimages.php dynamically creates xml content via PHP.

I read that this problem might have something to do with needing a request. I’ve never worked with Ajax in any way and don’t have time to do research.

How do I have to change this script so it works in as many browsers as possible?

The XML output of the PHP file looks like this

    <image url="MY_IMAGE_URL_1.jpg" number="1">
    <image url="MY_IMAGE_URL_2.jpg" number="2">
    <image url="MY_IMAGE_URL_3.jpg" number="3">
    <image url="MY_IMAGE_URL_4.jpg" number="4">

etc.

I would have thought the success function will be called when the file is loaded regardless of it’s content

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  1. Editorial Team
    Editorial Team
    2026-05-25T14:27:26+00:00Added an answer on May 25, 2026 at 2:27 pm

    First you should add an error event handler in your AJAX request:

    function getPictures() {
        $.ajax({
            type: "GET",
            url: "getimages.php",
            dataType: "xml",
            success: function(xml) {
                alert('success');
            },
            error: function(req, status) {
                alert(status);
            }
        });
    }
    

    Second, you need to close all the elements in your XML (ending them with />) as well as wrap them in a containing element as there can only be one root element in XML:

    <images>
        <image url="MY_IMAGE_URL_1.jpg" number="1" />
        <image url="MY_IMAGE_URL_2.jpg" number="2" />
        <image url="MY_IMAGE_URL_3.jpg" number="3" />
        <image url="MY_IMAGE_URL_4.jpg" number="4" />
    </images>
    
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