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Home/ Questions/Q 7416121
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T07:25:33+00:00 2026-05-29T07:25:33+00:00

The following sed command from commandline returns what I expect. $ echo ‘./Adobe ReaderScreenSnapz001.jpg’

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The following sed command from commandline returns what I expect.

$ echo './Adobe ReaderScreenSnapz001.jpg' | sed -e 's/.*\./After-1\./' 
After-1.jpg             <--- result

Howerver, in the following bash script, sed seeems not to act as I expect.

#!/bin/bash
beforeNamePrefix=$1
i=1
while IFS= read -r -u3 -d '' base_name; do
    echo $base_name
    rename=`(echo ${base_name} | sed -e s/.*\./After-$i./g)`
    echo 'Renamed to ' $rename
    i=$((i+1))
done 3< <(find . -name "$beforeNamePrefix*" -print0)

Result (with several files with similar names in the same directory):

./Adobe ReaderScreenSnapz001.jpg
Renamed to  After-1.         <--- file extension is missing.
./Adobe ReaderScreenSnapz002.jpg
Renamed to  After-2.
./Adobe ReaderScreenSnapz003.jpg
Renamed to  After-3.
./Adobe ReaderScreenSnapz004.jpg
Renamed to  After-4.

Where am I wrong? Thank you.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T07:25:34+00:00Added an answer on May 29, 2026 at 7:25 am

    Just use Parameter Expansion

    #!/bin/bash
    beforeNamePrefix="$1"
    i=1
    while IFS= read -r -u3 -d '' base_name; do
        echo "$base_name"
        rename="After-$((i++)).${base_name##*.}"
        echo "Renamed to $rename"
    done 3< <(find . -name "$beforeNamePrefix*" -print0)
    

    I also fixed some quoting to prevent unwanted word splitting

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