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Home/ Questions/Q 7614527
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T02:25:32+00:00 2026-05-31T02:25:32+00:00

The following site Writing Boot Sector Code provides a sample of code that prints

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The following site “Writing Boot Sector Code” provides a sample of code that prints ‘A’ to the screen when the system boots. From what I have been reading don’t you have to use INT opcode to get BIOS to do certain things? How does the code below, from the site referenced above work without using interrupts? What portion of code actually tells the hardware to print ‘A’ to the screen?

Code in question:

.code16
.section .text
.globl _start
_start:
  mov $0xb800, %ax
  mov %ax, %ds
  movb $'A', 0
  movb $0x1e, 1
idle:
  jmp idle 

APPENDING TO ORIGINAL QUESTION

If I use the following code does the BIOS call write to the text buffer for me? The buffer starting at address 0xb800?

   # Author: Matthew Hoggan
   # Date Created: Tuesday, Mar 6, 2012
   .code16                        # Tell assembler to work in 16 bit mode (directive)
   .section .text
   .globl _start                  # Help linker find start of program
   _start:
       movb $0x0e,     %ah        # Function to print a character to the screen                 
       movb $0x00,     %bh        # Indicate the page number
       movb $0x07,     %bl        # Text attribute
       mov  $'A',      %al        # Move data into low nibble                   
       int  $0x10                 # Video Service Request to Bios                             
   _hang:                         
       jmp  _hang                 
       .end   
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T02:25:33+00:00Added an answer on May 31, 2026 at 2:25 am

    Direct answer to your question: The line “movb $’A’, 0” effectively completes the print to the screen (and the following line, “movb $0x1e, 1” specifies what color it should be).

    Longer answer: The video hardware draws the screen based on the contents of memory. When in text mode, the video hardware starts drawing based on memory segment 0xB800. Whatever is at byte 0 defines the character to be drawn at the first text cell on the screen. The next byte defines the attributes (foreground color, background color, and blink status). This pattern repeats (char – attr – char – attr) throughout the entire screen.

    So, technically, my direct answer wasn’t true. The 2 ‘movb’ statements simply stage the letter ‘A’ to be printed. ‘A’ is not printed until the next time hardware refreshes the display based on the memory.

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