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Home/ Questions/Q 4257022
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T05:26:04+00:00 2026-05-21T05:26:04+00:00

The following snipit of code works fine, except for the fact that the resulting

  • 0

The following snipit of code works fine, except for the fact that the resulting attachment file name is blank in the email (the file opens as ‘noname’ in gmail). What am I doing wrong?

file_name = RecordingUrl.split("/")[-1]
            file_name=file_name+ ".wav"
            urlretrieve(RecordingUrl, file_name)

            # Create the container (outer) email message.
            msg = MIMEMultipart()
            msg['Subject'] = 'New feedback from %s (%a:%a)' % (
From, int(RecordingDuration) / 60, int(RecordingDuration) % 60)

            msg['From'] = "noreply@example.info"
            msg['To'] = 'user@gmail.com'
            msg.preamble = msg['Subject']                
            file = open(file_name, 'rb')
            audio = MIMEAudio(file.read())
            file.close()
            msg.attach(audio)

            # Send the email via our own SMTP server.
            s = smtplib.SMTP()
            s.connect()
            s.sendmail(msg['From'], msg['To'], msg.as_string())
            s.quit()
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  1. Editorial Team
    Editorial Team
    2026-05-21T05:26:05+00:00Added an answer on May 21, 2026 at 5:26 am

    You need to add a Content-Disposition header to the audio part of the message using the add_header method:

    file = open(file_name, 'rb')
    audio = MIMEAudio(file.read())
    file.close()
    audio.add_header('Content-Disposition', 'attachment', filename=file_name)
    msg.attach(audio)
    
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