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Home/ Questions/Q 8433975
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T06:31:58+00:00 2026-06-10T06:31:58+00:00

The following sql statement: SELECT profile_pic FROM (`member`) WHERE `active` = 1 produces the

  • 0

The following sql statement:

SELECT 
    profile_pic
FROM
    (`member`) 
WHERE 
    `active` = 1

produces the following result:

profile_pic
    1_1345694557.jpg
    <blank_value>
    <blank_value>
    <blank_value>

I want the “blank values” to default to “no_prof_thumb.jpg”.

So I created this statement:

SELECT 
    REPLACE(IF (CHAR_LENGTH(profile_pic) > 0, profile_pic, 'no_prof.jpg' ), '.jpg', '_thumb.jpg') AS profile_pic 
FROM 
    (`member`) 
WHERE 
    `active` = 1

Here is the result:

profile_pic
1_1345694557_thumb.jpg
no_prof_thumb.jpg
no_prof_thumb_thumb.jpg
no_prof_thumb_thumb_thumb.jpg

Why does _thumb keep appending itself to the value in the previous row?

How should I fix my expression?


Update

This issue occurs on a GoDaddy mySQL database. I reproduce when it connecting remotely through SQLyog and when I log into GoDaddy and run it through phpMyAdmin.

However, I cannot reproduce locally nor on sqlFiddle.
So it must be some kind of configuration issue.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T06:31:59+00:00Added an answer on June 10, 2026 at 6:31 am

    You needed to use IF outside the REPLACE statement like this.

    SELECT 
        IF (profile_pic = '', 'no_prof.jpg', 
            REPLACE(profile_pic, '.jpg', '_thumb.jpg')) AS profile_pic 
    FROM 
        (`member`) 
    WHERE 
        `active` = 1
    

    You can also use CASE statement instead of IF like this:

    SELECT
      CASE  profile_pic
        WHEN '' THEN 'no_prof.jpg'
        ELSE REPLACE(profile_pic, '.jpg', '_thumb.jpg')
      END AS profile_pic
    FROM member
    WHERE active = 1;
    

    See this fiddle

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