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Home/ Questions/Q 114439
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Asked: May 11, 20262026-05-11T02:51:39+00:00 2026-05-11T02:51:39+00:00

The following throws an InvalidCastException . IEnumerable<int> list = new List<int>() { 1 };

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The following throws an InvalidCastException.

IEnumerable<int> list = new List<int>() { 1 }; IEnumerable<long> castedList = list.Cast<long>(); Console.WriteLine(castedList.First()); 

Why?

I’m using Visual Studio 2008 SP1.

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  1. 2026-05-11T02:51:39+00:00Added an answer on May 11, 2026 at 2:51 am

    That’s very odd! There’s a blog post here that describes how the behaviour of Cast<T>() was changed between .NET 3.5 and .NET 3.5 SP1, but it still doesn’t explain the InvalidCastException, which you even get if you rewrite your code thus:

    var list = new[] { 1 }; var castedList = from long l in list select l; Console.WriteLine(castedList.First()); 

    Obviously you can work around it by doing the cast yourself

    var castedList = list.Select(i => (long)i); 

    This works, but it doesn’t explain the error in the first place. I tried casting the list to short and float and those threw the same exception.

    Edit

    That blog post does explain why it doesn’t work!

    Cast<T>() is an extension method on IEnumerable rather than IEnumerable<T>. That means that by the time each value gets to the point where it’s being cast, it has already been boxed back into a System.Object. In essence it’s trying to do this:

    int i = 1; object o = i; long l = (long)o; 

    This code throws the InvalidCastException you’re getting. If you try to cast an int directly to a long you’re fine, but casting a boxed int back to a long doesn’t work.

    Certainly an oddity!

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