Question

The following will ensure that any large numbers will only be precise to the hundredths place (related to this answer):

public function round( sc:Number ):Number
{
    sc = sc * 100;
    sc = Math.floor( sc );
    sc = sc / 100;

    return sc;
}

What is the optimal way to round my numbers to the precision of .05? Is there something clever to be done with bit-shifting to get this result? For example, I would like:

3.4566 = 3.45

3.04232 = 3.05

3.09 = 3.1

3.32 = 3.3

Answer 1

You could multiply by 20, round, then divide by 20.

Edit: You will want to use Math.round() instead of Math.floor(), otherwise your test case 3.09 will turn into 3.05.