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Home/ Questions/Q 6705637
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Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T07:25:37+00:00 2026-05-26T07:25:37+00:00

The following works perfectly until I try to replace the hard coded service_id with

  • 0

The following works perfectly until I try to replace the hard coded “service_id” with the passed string variable id_name.

Is there a way to pass a variable into this part of the options?, If so, how be it?

Working version:

function deleteRecord(id)
{
$.ajax({
  'url': url_root+'admin/index',
  'type': 'POST',
  'data': {"service_id" : id,
          'ajax_name': 'services_list_table'
          },
  'dataType': 'json',
  'success': function(data)
        {
            $("#ajax_services_table").html(data.html);
        }
    });
}

Not working version (passing in the “service_id” as a variable)

function deleteRecord(id,id_name)
{
    $.ajax({
      'url': url_root+'admin/index',
      'type': 'POST',
      'data': {id_name : id,
              'ajax_name': 'services_list_table'
              },
      'dataType': 'json',
      'success': function(data)
            {
                $("#ajax_services_table").html(data.html);
            }
    });
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T07:25:37+00:00Added an answer on May 26, 2026 at 7:25 am

    You would need to do…

    var data = { 'ajax_name': 'services_list_table' };
    
    data[id_name] = id;
    

    Then pass data to data of your $.ajax().

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