Question

The function cannot initialize an array because sizeof() returns bytes of an int pointer
not the size the memory pointed by myArray.

 void assignArray(int *myArray)
 {
     for(int k = 0; k < sizeof(myArray); ++k)
     {
         myArray[k] = k;
     }
 }

Are there other problems ?

Thanks

Answer 1

I don’t see other problems. However, you probably wanted this:

template<int sz>
void assignArray(int (&myArray)[sz])
{
    for(int k = 0; k < sz; ++k)
    {
        myArray[k] = k;
    }
}

Unless, of course, even the compiler doens’t know how big it is at compile time. In which case you have to pass a size explicitly.

void assignArray(int* myArray, size_t sz)
{
    for(int k = 0; k < sz; ++k)
    {
        myArray[k] = k;
    }
}

If you don’t know the size, you have a design error.

http://codepad.org/Sj2D6uWz