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Home/ Questions/Q 7398215
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T03:50:35+00:00 2026-05-29T03:50:35+00:00

The function const is defined in Prelude as: const x _ = x In

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The function const is defined in Prelude as:

const x _ = x

In GHCi, when I tried

Prelude> const 6 5  -> Gives 6

But when I tried

Prelude> const id 6 5 -> Gives 5

Even after making changes like

Prelude> (const id 6) 5 -> Gives 5

Shouldn’t this function give 6 as the output of function id has type id :: a -> a which should bind like

Prelude> (const 6) 5 -> Gives 6

Why does function const behave differently?

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  1. Editorial Team
    Editorial Team
    2026-05-29T03:50:36+00:00Added an answer on May 29, 2026 at 3:50 am

    You seem to be thinking that this is equivalent to const (id 6) 5, where id 6 evaluates to 6, but it isn’t. Without those parentheses, you’re passing the id function as the first argument to const. So look at the definition of const again:

    const x _ = x
    

    This means that const id 6 = id. Therefore, const id 6 5 is equivalent to id 5, which is indeed 5.

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