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Home/ Questions/Q 7885915
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T05:11:27+00:00 2026-06-03T05:11:27+00:00

The html code: <table id=’table’> <tr> <td>..</td> </tr> </table> The js code with jquery:

  • 0

The html code:

<table id='table'>
    <tr>
        <td>..</td>
    </tr>
</table>

The js code with jquery:

var l1 = $('#table > tr').length;
var l2 = $('#table tr').length;
alert(l1+','+l2);​

The result:

 0,1

Why the first #table > tr get 0?

You can see a live demo from here: http://jsfiddle.net/Freewind/PmsFQ/

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T05:11:28+00:00Added an answer on June 3, 2026 at 5:11 am

    Because the direct children of a <table> can only be <thead>, <tbody>, or <tfoot> (or <colgroup> or <caption>, but those don’t contain rows).

    The browser’s DOM will implicitly wrap stray <tr>s in a <tbody>. (for browsers that don’t do this, jQuery fakes it instead)

    You need to write $('#table > tbody > tr').

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