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Home/ Questions/Q 3871970
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Editorial Team
  • 0
Editorial Team
Asked: May 19, 20262026-05-19T21:52:31+00:00 2026-05-19T21:52:31+00:00

the if part is not working var name = $(#name); $.ajax({ type: get, url:

  • 0

the if part is not working

var name = $("#name");

$.ajax({
    type:       "get",
    url:        "test.jsp",
    data:           "name="+name,
    success:    function(msg) {

        if( msg == "available" )
        {
            // you conditional code here
            // i want to display a image here with id nameInfo
            $('#result').hide();

            $("#result").html(msg).fadeIn("slow");
        }
    }
});
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T21:52:31+00:00Added an answer on May 19, 2026 at 9:52 pm
    $.ajax({
        type:       "get",
        url:        "test.jsp",
        data:           "name="+name,
        success:    function(msg) {
    
            if( msg == 'available' )
            {
                // you conditional code here
            }
    
            $('#result').hide();
    
            $("#result").html(msg)
            .fadeIn("slow");
        }
    });
    
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