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Home/ Questions/Q 8795515
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T23:24:10+00:00 2026-06-13T23:24:10+00:00

The if statement in this function, works without vectorization? def K(T0,z,v): for i in

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The if statement in this function, works without vectorization?

def K(T0,z,v):

    for i in range(len(T0)-1):
        GDens[i+1]=(Dens[i+1]-Dens[i])/(z[i+1]-z[i])

    for i in range(len(T0)):
        B[i]=(((ws/Dens0)*k0)**2)*np.exp(-2*alfa*z[i])-((g/Dens0)*GDens[i])

    for i in range(len(T0)):
        if B[i]>0:
            kz[i]=((0.05*h1)**2)*np.sqrt(B[i])+kmin
        else:
            kz[i]=kmin
    kfinal=kz
    return kfinal
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  1. Editorial Team
    Editorial Team
    2026-06-13T23:24:13+00:00Added an answer on June 13, 2026 at 11:24 pm

    I’m not sure what you’re asking but this is how you can vectorize this code:

     GDens = np.zeros_like(z)
     GDens[:-1] = (Dens[1:] - Dens[:-1]) / (z[1:] - z[:-1])
     B = (((ws/Dens0)*k0)**2)*np.exp(-2*alfa*z)-((g/Dens0)*GDens)
     kz = np.where(B > 0, ((0.05*h1)**2)*np.sqrt(B)+kmin, kmin)
    
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