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Home/ Questions/Q 8721955
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T07:18:25+00:00 2026-06-13T07:18:25+00:00

The input size of a certain algorithm is n^2+n*m. Its running time is O(m*n^3).

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The input size of a certain algorithm is n^2+n*m. Its running time is O(m*n^3). Can the running time be considered polynomial in the input size?

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  1. Editorial Team
    Editorial Team
    2026-06-13T07:18:26+00:00Added an answer on June 13, 2026 at 7:18 am

    Run time T(n,m) is said to be polynomial in the input size S(n,m) = n^2+n*m if there is a polynomial in S that is an upper bound on T(n,m).

    Consider the polynomial S^2(n,m) = (n^2+n*m)^2 = n^4 + 2(n^2)n*m + (n^2)(m^2). Since n^4 and (n^2)(m^2) are squares of positive integers they are positive, so S^2(n,m) > 2(n^2)n*m > n^3 * m.

    Since T(n,m) is O(n^3 * m) and S^2(n,m) > n^3 * m we have T(n,m) is O(S^2(n,m)) hence run time is bounded by a polynomial in input size.

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