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Home/ Questions/Q 7685985
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T19:22:36+00:00 2026-05-31T19:22:36+00:00

The issue I have is that I want to parse strings in order, so

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The issue I have is that I want to parse strings in order, so for instance, parsing “one three two”, adding that to another string, and printing “one three two”. I’m using rangeOfString:, but when I parse that string, it returns “one two three”. I know that the order of parsing in my case is the placement of the if statements, but how do I parse that string in order? Here is my code:

NSString *string = @"one three two";
NSString *newString;

if ([string rangeOfString:@"one"].location != NSNotFound)
{
    newString = [newString stringByAppendingString:@"one"];
}
if ([string rangeOfString:@"two"].location != NSNotFound)
{
    newString = [newString stringByAppendingString:@"two"];
}
if ([string rangeOfString:@"three"].location != NSNotFound)
{
    newString = [newString stringByAppendingString:@"three"];
}

NSLog(@"%@",newString);
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  1. Editorial Team
    Editorial Team
    2026-05-31T19:22:38+00:00Added an answer on May 31, 2026 at 7:22 pm

    You are doing this wrong, you should use componentsSeparatedByString: and sorting:

    NSString *stringWithNumbersOrdered(NSString *input)
    {
        static NSArray *numberStrings = nil;
    
        if (!numberStrings)
        {
            numberStrings = [NSArray arrayWithObjects:@"zero", @"one", @"two", @"three", @"four", @"five", @"six", @"seven", @"eight", @"nine", /* etc. */ nil];
        }
    
        NSArray *components = [input componentsSeparatedByString:@" "];
        NSArray *componentsSorted = [components sortedArrayUsingComparator:^NSComparisonResult(id obj1, id obj2) {
            int value1 = [numberStrings indexOfObject:obj1];
            int value2 = [numberStrings indexOfObject:obj2];
    
            return value1 - value2;
        }];
    
        return [componentsSorted componentsJoinedByString:@" "];
    }
    
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