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Home/ Questions/Q 7512591
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T23:54:36+00:00 2026-05-29T23:54:36+00:00

The issue is that it is calling the original beamthemup2.bat file, not the one

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The issue is that it is calling the original beamthemup2.bat file, not the one copied.

@ECHO OFF
for /d %%X in (*) do (
    copy "beamthemup2.bat" "%%X" 
    @echo "%%X\beamthemup2.bat"
    pause
    call "%%X\beamthemup2.bat"
)

UPDATE

This is the second bat file. It seems it is copying the and running the correct batch file. Here is the problem though. When running the above batch file first %cd% is returning the path of the first batch file, however if I run the second one by itself in the folder that I wanted it copied to, %cd% returns the correct folder.

@ECHO OFF
for /r %%X in (*) do (

    "c:\Program Files\7-Zip\7z.exe" a -tzip "%cd%" "%%X"
    @ECHO %cd%
    pause

)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T23:54:38+00:00Added an answer on May 29, 2026 at 11:54 pm

    Your current working directory is still the directory you started the first batch file from. Running the second batch file doesn’t change the working directory.

    Try adding cd %~dp0 to your second batch file (after @ECHO OFF). That will cd to the directory the batch file is in.

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