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Home/ Questions/Q 7916445
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T14:48:39+00:00 2026-06-03T14:48:39+00:00

The k-medoids in the clara() function uses distance to form clusters so I get

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The k-medoids in the clara() function uses distance to form clusters so I get this pattern:

a <- matrix(c(0,1,3,2,0,.32,1,.5,0,.35,1.2,.4,.5,.3,.2,.1,.5,.2,0,-.1), byrow=T, nrow=5)
cl <- clara(a,2)
matplot(t(a),type="b", pch=20, col=cl$clustering) 

clustering by clara()

But I want to find a clustering method that assigns a cluster to each line according to its trend, so lines 1, 2 and 3 belong to one cluster and lines 4 and 5 to another.

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  1. Editorial Team
    Editorial Team
    2026-06-03T14:48:41+00:00Added an answer on June 3, 2026 at 2:48 pm

    This question might be better suited to stats.stackexchange.com, but here’s a solution anyway.

    Your question is actually “How do I pick the right distance metric?”. Instead of Euclidean distance between these vectors, you want a distance that measures similarity in trend.

    Here’s one option:

    a1 <- t(apply(a,1,scale))
    a2 <- t(apply(a1,1,diff))
    
    cl <- clara(a2,2)
    matplot(t(a),type="b", pch=20, col=cl$clustering) 
    

    enter image description here

    Instead of defining a new distance metric, I’ve accomplished essentially the same thing by transforming the data. First scaling each row, so that we can compare relative trends without differences in scale throwing us off. Next, we just convert the data to the differences.

    Warning: This is not necessarily going to work for all “trend” data. In particular, looking at successive differences only captures a single, limited facet of “trend”. You may have to put some thought into more sophisticated metrics.

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