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Editorial Team
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Asked: 2026-05-16T11:00:09+00:00

The link below works fine unless the variable $row[title] contains a double-quotation mark ().

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The link below works fine unless the variable $row["title"] contains a double-quotation mark (“). In that case, everything after the quotation marks is omitted in the link.

How can I make the link include everything after a double-quotation mark?

Thanks in advance,

John

echo '<td class="sitename2"><a href="http://www...com/.../comments/index.php?submission='.$row["title"].'">'.$row["countComments"].' COMMENTS</a></td>';
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1 Answer

  1. Editorial Team

    Always use urlencode for parts of a URL which might need to contain anything unusual….

    echo '<td class="sitename2">'.
  '<a href="http://www...com/.../comments/index.php?submission='.
  urlencode($row["title"]).
  '">'.
  $row["countComments"].' COMMENTS</a></td>';

    If you want to get into the standards, refer to RFC3986 which defines the safe, or ‘unreserved’ character as follows:

    unreserved = ALPHA / DIGIT / “-” / “.” / “_” / “~”

    urlencode makes sure that a value you want to include in a URL obeys these standards

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