Question

The list sort() method is a modifier function that returns None.

So if I want to iterate through all of the keys in a dictionary I cannot do:

for k in somedictionary.keys().sort():     dosomething() 

Instead, I must:

keys = somedictionary.keys() keys.sort() for k in keys:     dosomething() 

Is there a pretty way to iterate through these keys in sorted order without having to break it up in to multiple steps?

Answer 1

for k in sorted(somedictionary.keys()):     doSomething(k) 

Note that you can also get all of the keys and values sorted by keys like this:

for k, v in sorted(somedictionary.iteritems()):    doSomething(k, v)