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Home/ Questions/Q 6816893
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T20:58:51+00:00 2026-05-26T20:58:51+00:00

the long hand if in javascript would look: function somefunction(param){ if(typeof(param) != ‘undefined’){ var

  • 0

the long hand if in javascript would look:

function somefunction(param){

    if(typeof(param) != 'undefined'){
           var somevar = param;
         } else {

           alert('ERROR: missing parameter in somefunction. Check your form'); 
           return;

         }

}

AND MY SHORT HAND VERSION IS:

function somefunction(param){

    param = typeof(param) != 'undefined' ? param : function(){alert('ERROR: missing parameter in somefunction. Check your form'); return;}

}

BUT it does not work.

How could I?

Thank you

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T20:58:51+00:00Added an answer on May 26, 2026 at 8:58 pm

    You are only declaring the function. you have to execute it. Add () next to the definition ..

    function somefunction(param){
        param = typeof(param) != 'undefined' ?
                    param :
                    function() {
                        alert('ERROR: missing parameter in somefunction. Check your form'); 
                        return false;
                    }();
    }
    

    EDIT: The above is not functionally equivalent to the original as the function itself doesn’t return anything and doesn’t end the function execution.

    function somefunction(param) {
        if (typeof(param) == 'undefined') {
            alert('ERROR: missing parameter in somefunction. Check your form'); 
            return false;
        }
    
        // Use param
    }
    
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