Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6818517
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 26, 20262026-05-26T21:11:17+00:00 2026-05-26T21:11:17+00:00

The most convenient method to read an image from a source ( File s,

  • 0

The most convenient method to read an image from a source (Files, InputStreams, URLs) is:

BufferedImage myImage = ImageIO.read( source );

But then, how to convert myImage to a BufferedImage.TYPE_USHORT_565_RGB format?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-26T21:11:18+00:00Added an answer on May 26, 2026 at 9:11 pm

    You can create a new BufferedImage of the required type and then draw the original image on it, something like:

        BufferedImage bufImg = ImageIO.read( imageURL );
        BufferedImage convertedImg = new BufferedImage(bufImg.getWidth(), bufImg.getHeight(), BufferedImage.TYPE_USHORT_565_RGB);
        convertedImg.getGraphics().drawImage(bufImg, 0, 0, null);
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I was wondering what would be the most simple but secure method for the
What's the best, most convenient, and most Apple-permitted way of streaming video from the
What is the most convenient way to extract a specified byte range of a
Most of my C/C++ development involves monolithic module files and absolutely no classes whatsoever,
What is the most convenient way to apply some custom styling to an individual
Sorry for the long title, but it seems most descriptive for my question. Basically,
I'm a beginner in Objective-C and I'm trying to find the most convenient way
Someone might yell at me to read the faqqing faq, but I'm in a
The default split method in Python treats consecutive spaces as a single delimiter. But
What is the most convenient or common 3D format for Python? In terms of

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.