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Home/ Questions/Q 513235
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T07:24:05+00:00 2026-05-13T07:24:05+00:00

The MVC pattern wants that Model dispatches change status events to View. Which is

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The MVC pattern wants that Model dispatches change status events to View.
Which is the best implementation of this comunication if the Model is a simple javabean with setter and getter methods?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T07:24:06+00:00Added an answer on May 13, 2026 at 7:24 am

    In your bean, allow the registration of PropertyChangeListeners, it’s the designated observer class for change notification on java beans.

    Example bean with PropertyChangeListener support:

    public class TestBean {
    
        private transient final List<PropertyChangeListener> listeners = new ArrayList<PropertyChangeListener>();
    
        private String name;
    
        public void addPropertyChangeListener (PropertyChangeListener listener) {
            listeners.add(listener);
        }
    
        public void removePropertyChangeListener (PropertyChangeListener listener) {
            listeners.remove(listener);
        }
    
        private void firePropertyChange (String property, Object oldValue, Object newValue) {
    
            if (oldValue == newValue || oldValue != null && oldValue.equals(newValue)) {
                return;
            }
    
            PropertyChangeEvent evt = new PropertyChangeEvent(this, property, oldValue, newValue);
            for (PropertyChangeListener listener : new ArrayList<PropertyChangeListener>(listeners)) {
                listener.propertyChange(evt);
            }
        }
    
        public String getName () {
            return name;
        }
    
        public void setName (String name) {
    
            firePropertyChange("name", this.name, this.name = name);
        }
    }
    
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