Question

The official site shows the following function

square = (x) -> x * x 

Then you can do something like

square(4)

Is it possible to do the above in a single line using anonymous function? I’m thinking of something like the following

(f = do (x) -> x * x) (4)

My code doesn’t compile but I’m hoping the intent is clear enough

Answer 1

I’m not sure what the application for this is but you can substitute the definition of square for square if you wrap it in parentheses:

((x) -> x*x)(4) #evaluates to 16