Question

The original logfile sample:

“GET
/dynamic_preroll_playlist.fmil?domain=13nwuc&width=480&height=360&imu=medrect&pubchannel=filmannex&ad_unit=category_2&sdk_ver=2.4.1.3&embeddedIn=http%3A%2F%2Fwww.filmannex.com%2Fmovie%2Fend-of-the-tunnel%2F20872&sdk_url=http%3A%2F%2Fstatic2.filmannex.com%2Fflash%2F&viewport=10,261,971,0,981,10,10,261
HTTP/1.1″, 200, 201, 1516, 16363,
“http://static2.filmannex.com/flash/yume_ad_library.swf”,
pl.networks.com, “Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 6.0;
FunWebProducts; GTB7.3; SLCC1; .NET CLR 2.0.50727; .NET CLR 3.5.30729;
.NET CLR 3.0.30618; FunWebProducts; .NET4.0C)”,
“24_100_150_188_jZKFKQQjdRNM6e”,
“0rO0ABXd8AAAACgAAASQAAAaLAAAGiwAAASgAAAaLAAAGiwAAAVoAAAaLAAAGiwAAAVkAAAaKAAAGiwAAAdwAAAaKAAAGiwAAAhIAAAaKAAAGiwAAAhUAAAaKAAAGiwAAAhYAAAaKAAAGiwAAAhsAAAaKAAAGiwAAAiwAAAaKAAAGiw**”,
“-“, “-“, “@YD_1;233_2739”, -, “-“, “24.100.150.188”, “199.127.205.6”

The required output is the 5rd and 6th field of viewport:

981 10

I got the gawk code below which yields the 3rd and 4th fields:

910 0

gawk 'match($0, /&viewport=[0-9]+,[0-9]+,([0-9]+),([0-9]+)/, m){print m[1], m[2]}' filename

Can anyone help me with this problem? Just a little change to the gawk command fetch the 5th and 6th parameters of viewport?

Any ideas? Thanks so much in advance 🙂

Answer 1

this command will do what you want:

awk '{split($0,a,"viewport=");split(a[2],b,",");print b[5],b[6]}' filename

gives:

981 10

If you do want the modified gawk command:

gawk 'match($0, /&viewport=[0-9]+,[0-9]+,([0-9]+),([0-9]+),([0-9]+),([0-9]+),([0-9]+)/, m){print m[3], m[4]}' filename

will also work.

I think the first solution is cleaner/clearer and also easier to modify.