Question

The out put is 12 12 for the following code.

var omg = function(){

        var space = {q:12} ;

        var sq = [];

        sq[0] = function(){
                console.log(space.q);
                space.q = 14;
        };

        sq[1] = function(){
                console.log(space.q);
        };



        return sq;

};

omg()[0]();
omg()[1]();
~                           

Why is the output not 12 14 ?!?

Answer 1

Each omg() call returns a new function. Hence, the omg()[0]() call changes the local value of q of that particular instance. I think if you did it like this:

var a = omg()
a[0](); 
a[1](); 

you’d get the expected output.