Question

the php file:

if (!isset($servers[$ext])){
    die('no match data!');
}
return $output;

the html file:

$.ajax({
    type:"get",
    url:"/tests/api/?u="+u,
    dataType:"json",
    data:"",
    success:function result(data){
        $("#show").html(data);
        $("#show").show();


    }
});

when happens no match data!'. the html file can’t output no match data! tips, how to output it, thank you.

there is a response (no match data!)in the firebug console.but the html file can’t output it.now, i want to the html file can output the no match data! tips how should i do

Answer 1

If you die you won’t reach the return. @PhpMyCoder

   if (!isset($servers[$ext])){
       $output="no match data!";
    }
    return(json_encode($output));