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Home/ Questions/Q 7882905
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T04:23:45+00:00 2026-06-03T04:23:45+00:00

The picking itself is easy, but I’m having trouble making sure I can’t place

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The picking itself is easy, but I’m having trouble making sure I can’t place the points on the same spot. I could of course re-random, but is there a better way? Thanks a lot!

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  1. Editorial Team
    Editorial Team
    2026-06-03T04:23:46+00:00Added an answer on June 3, 2026 at 4:23 am

    choosing K indices from N possible locations randomly is equivalent to first random shuffling the array and then take the first K indices. If you program in c++ (which is what you are giving as tag), it can be as easy as:

    first, make your 2D array flat, say its stored in a vector: vector elems;

    #include <vector>
    #include <algorithm>
    using namespace std;
    
    .... initialize elems to whatever you want, here all zeros ......
    
    vector<int> elems (N*M, 0);
    
    // assigning your indices from 0 to elems.size()-1
    vector<int> index (elems.size());
    for (int i=0; i<index.size(); i++)
    {
        index[i] = i;
    }
    
    // now random permute
    random_shuffle (index.begin(), index.end());
    
    // now assign the elements to whatever you want, here assign them to 1
    elems[index[0]] = 1;
    elems[index[1]] = 1;
    
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