Question

the problem i am face right now is i can’t pass a variable from iphone to php page.First i want to pass the country name to php page from iphone.

This is the php code:

$coname=$_POST["c_name"];

    $con = mysql_connect("url","username","password");
        if (!$con){die('Could not connect: ' . mysql_error());}
            mysql_select_db("Appiness", $con);

    header("Content-Type: text/xml");    
    $bilgi= mysql_query("SELECT age,wname,slid,sex FROM user WHERE user.c_name='".$coname."'");
    while($sutun= mysql_fetch_array($bilgi))
    {
        echo $sutun["age"];
        echo $sutun["wname"];
        echo $sutun["sex"];        
        echo $sutun["slid"];    
    } 

    mysql_close($con);

this is the part i ‘ve call the php page in xcode

 NSString *country=[[NSUserDefaults standardUserDefaults]objectForKey:@"namecountry"];
//url's
NSURL *url = [NSURL URLWithString:@"http://www.trevesstudios.com/get.php"];
ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:url];

[request setPostValue:country forKey:@"c_name"];
[request setRequestMethod:@"POST"];
[request setValidatesSecureCertificate:NO];
[request setDelegate:self];
[request startSynchronous];

response = [request responseString];
NSLog(@"%@",response);

Can anyone help me for why this code is not working btw when i try to change the WHERE c_name=’France’ it works the the problem is the variable.Can anybody helpme?

Answer 1

A few things to check:

1. what is country value after reading it from NSUserDefaults?

2. what does NSLog(@"%@",response); print out?

3. in your PHP, what is $coname?

4. is $_POST defined? is $_GET defined? could you print out $_REQUEST content (print_r($_REQUEST))?

EDIT:

can you put this statement

echo print_r($_REQUEST);

before $coname=$_POST["c_name"];?

can you add this statement:

 echo mysql_errno($con) . ": " . mysql_error($con) . "\n";

after executing mysql_query?

what does it output?

EDIT2:

With the echoes we added above, we now know that the post parameter is arriving at the server. Are you sure that there are data stored for France in your database? mysql_error did not return any error (0: in the output), so everything went ok… it seems that the query returned no data, but it did not fail…

Anyway, just as a further check, could you add this more statement before executing mysql_query?

echo "SELECT age,wname,slid,sex FROM user WHERE user.c_name='".$coname."'";

so we will see what the query looks like…

EDIT3:

please, replace:

$coname=$_POST["c_name"];

by

$coname=$_REQUEST["c_name"];

EDIT 4:

$bilgi= mysql_query("SELECT age,wname,slid,sex,c_name FROM user");
while($sutun= mysql_fetch_array($bilgi))
{
    echo $sutun["age"];
    echo $sutun["wname"];
    echo $sutun["sex"];        
    echo $sutun["slid"];    
    echo $sutun["c_name"];    
}