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Home/ Questions/Q 7794617
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T22:49:35+00:00 2026-06-01T22:49:35+00:00

The problem I have : I click add I select 2nd option I click

  • 0

The problem I have :

I click “add”
I select 2nd option
I click “add”

Problem : my first select-list’s selected option index = 0;
This should not happen, but I can’t figure out why it does it anyway. Can anyone tell me what I did wrong?

<script type="text/javascript">
function add(){
var div =document.getElementById('ruletemplate').cloneNode(true);

document.getElementById('rules').innerHTML += div.innerHTML;
return false;
}

</script>
<div id="ruletemplate" style="display: none;">
<div >
    <label for="rule">Rule</label>
    <select name="rules[][option]">
        <option>MAX PERS</option>
        <option>MIN PERS</option>
    </select>
    <input name="rule[][amount]" type="text"/>
</div>
</div>
<form>
<div  id="rules" >

</div>
<a id="addRule" href="" onclick="javascript: add(); return false;">add</a>
<input type="Submit" value="Save"  />
</form>
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  1. Editorial Team
    Editorial Team
    2026-06-01T22:49:37+00:00Added an answer on June 1, 2026 at 10:49 pm

    The reason it is doing that is you are setting the innerHTML which means the entire thing is reparsed. You will need to append the element to container instead. Try this it should keep each select’s position.

    function add(){
    var div =document.getElementById('ruletemplate').cloneNode(true);
    div.style.display='block';
    document.getElementById('rules').appendChild(div);
    return false;
    }
    
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