Question

The problem is probably quite simple.

$q = "SELECT id FROM users
        WHERE name LIKE '%$u%' OR active LIKE '%$u%'";
        echo $q;
$u = mysql_query($q) or die("There is a server error : " . mysql_error());
$u = mysql_fetch_array($u);
        print_r($u);

But it returns me

[id] => 6

When I execute the query in Mysql Workbench it returns

6
7
8

It’s probably a fetching problem but I don’t understand why.
Thanks 🙂

Answer 1

mysql_fetch_array() only returns one row. To get more rows, you need a loop.

Also mysql_fetch_array() returns both a string association and a integral indexing.
What you want to use is mysql_fetch_assoc() like so:

while ($data = mysql_fetch_assoc($u)) {
   echo $data['id'];
}