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Home/ Questions/Q 8328457
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T01:27:04+00:00 2026-06-09T01:27:04+00:00

The problem is that I get only the last value comming from the Table.

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The problem is that I get only the last value comming from the Table. I think its because I am building the array while referencing its values to the same object, and it keeps changing. I know while loop doesnt create a new scope for each iteration which IS the problem.

What’s the best way to get a new scope for each iteration?

Code:

    $namesArray= array();
        while ($row=mysql_fetch_array($result))
        {
        $nameAndCode->code = $row['country_code2'];
        $nameAndCode->name = $row['country_name'];           
        array_push($namesArray,$nameAndCode);


        } 
return $namesArray;
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T01:27:06+00:00Added an answer on June 9, 2026 at 1:27 am

    You need to create a new object on each iteration:

    while ($row=mysql_fetch_array($result))
    {
        $nameAndCode = new stdClass;
        $nameAndCode->code = $row['country_code2'];
        $nameAndCode->name = $row['country_name'];           
        $namesArray[] = $nameAndCode;
    } 
    

    Otherwise you’re referencing the same object over and over, and just overwriting its values.

    You also can do this with arrays if you don’t require objects:

    while ($row=mysql_fetch_array($result))
    {
        $nameAndCode = array();
        $nameAndCode['code'] = $row['country_code2'];
        $nameAndCode['name'] = $row['country_name'];           
        $namesArray[] = $nameAndCode;
    } 
    

    Or more concisely:

    while ($row=mysql_fetch_array($result))
    {
        $namesArray[] = array( 
            'code' => $row['country_code2'],
            'name' => $row['country_name']
        );
    } 
    
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