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Home/ Questions/Q 3242944
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T18:22:30+00:00 2026-05-17T18:22:30+00:00

The proper way to iterate is to use iterators. However, I think by erasing,

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The proper way to iterate is to use iterators. However, I think by erasing, the iterator is invalidated.

Basically what I want to do is:

for(iterator it = begin; it != end; ++it)
{
    if(it->somecondition() )
    {
     erase it
    }

}

How could I do this without v[i] method?

Thanks

struct RemoveTimedEvent
{
    bool operator()(const AguiTimedEvent& pX, AguiWidgetBase* widget) const 
    {
        return pX.getCaller() == widget;
    }
};

void AguiWidgetContainer::clearTimedEvents( AguiWidgetBase* widget )
{
    std::vector<AguiTimedEvent>::iterator it = std::remove_if(timedEvents.begin(),
        timedEvents.end(), RemoveTimedEvent());
    timedEvents.erase(it, timedEvents.end());

}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T18:22:30+00:00Added an answer on May 17, 2026 at 6:22 pm

    erase() returns a new iterator:

    for(iterator it = begin; it != end(container) /* !!! */;)
    {
        if (it->somecondition())
        {
            it = vec.erase(it);  // Returns the new iterator to continue from.
        }
        else
        {
            ++it;
        }
    }
    

    Note that we can no longer compare it against a precalculated end, because we may erase it and therefore invalidate it. We must get the end explicitly each time.

    A better method might be to combine std::remove_if and erase(). You change from being O(N2) (every element gets erased and shifted as you go) to O(N):

    iterator it = std::remove_if(begin, end, pred);
    vec.erase(it, vec.end());
    

    Where pred is your removal predicate, such as:

    struct predicate // do choose a better name
    {
        bool operator()(const T& pX) const // replace T with your type
        {
            return pX.shouldIBeRemoved();
        }
    };
    
    iterator it = std::remove_if(begin, end, predicate());
    vec.erase(it, vec.end());
    

    In your case, you can make it pretty general:

    class remove_by_caller
    {
    public:
        remove_by_caller(AguiWidgetBase* pWidget) :
        mWidget(pWidget)
        {}
    
        // if every thing that has getCaller has a base, use that instead
        template <typename T> // for now a template
        bool operator()(const T& pX) const
        {
            return pX.getCaller() == mWidget;
        }
    
    private:
        AguiWidgetBase* mWidget;
    };
    
    std::vector<AguiTimedEvent>::iterator it =
        std::remove_if(timedEvents.begin(), timedEvents.end(), remove_by_caller(widget));
    timedEvents.erase(it, timedEvents.end());
    

    Note lambda’s exist to simplify this process, both in Boost and C++11.

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