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Home/ Questions/Q 521355
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T08:14:30+00:00 2026-05-13T08:14:30+00:00

The Python version of Google protobuf gives us only: SerializeAsString() Where as the C++

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The Python version of Google protobuf gives us only:

SerializeAsString()

Where as the C++ version gives us both:

SerializeToArray(...)
SerializeAsString()

We’re writing to our C++ file in binary format, and we’d like to keep it this way. That said, is there a way of reading the binary data into Python and parsing it as if it were a string?

Is this the correct way of doing it?

binary = get_binary_data()
binary_size = get_binary_size()

string = None
for i in range(len(binary_size)):
   string += i

message = new MyMessage()
message.ParseFromString(string)

Update:

Here’s a new example, and a problem:

message_length = 512

file = open('foobars.bin', 'rb')

eof = False
while not eof:

    data = file.read(message_length)
    eof = not data

    if not eof:
        foo_bar = FooBar()
        foo_bar.ParseFromString(data)

When we get to the foo_bar.ParseFromString(data) line, I get this error:

Exception Type: DecodeError
Exception Value: Too many bytes when decoding varint.

Update 2:

It turns out, that the padding on the binary data was throwing protobuf off; too many bytes were being sent in, as the message suggests (in this case it was referring to the padding).

This padding comes from using the C++ protobuf function, SerializeToArray on a fixed-length buffer. To eliminate this, I have used this temproary code:

message_length = 512

file = open('foobars.bin', 'rb')

eof = False
while not eof:

    data = file.read(message_length)
    eof = not data

    string = ''
    for i in range(0, len(data)):
        byte = data[i]
        if byte != '\xcc': # yuck!
            string += data[i]

    if not eof:
        foo_bar = FooBar()
        foo_bar.ParseFromString(string)

There is a design flaw here I think. I will re-implement my C++ code so that it writes variable length arrays to the binary file. As advised by the protobuf documentation, I will prefix each message with it’s binary size so that I know how much to read when I’m opening the file with Python.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T08:14:31+00:00Added an answer on May 13, 2026 at 8:14 am

    I’m not an expert with Python, but you can pass the result of a file.read() operation into message.ParseFromString(...) without having to build a new string type or anything.

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