The query I have below will only show me one result even if there are multiple matching entries (completely or partially matching). How do I fix it so it will return all matching entries:
//$allowed is a variable from database.
$sql = "SELECT `users`.`full_name`, `taglines`.`name`, `users`.`user_id` FROM
`users` LEFT JOIN `taglines` ON `users`.`user_id` = `taglines`.`person_id`
WHERE ( `users`.`user_settings` = '$allowed' ) and ( `users`.`full_name`
LIKE '%$q%' ) LIMIT $startrow, 15";
$result = mysql_query($sql);
$query = mysql_query($sql) or die ("Error: ".mysql_error());
$num_rows1 = mysql_num_rows($result);
if ($result == "")
{
echo "";
}
echo "";
$rows = mysql_num_rows($result);
if($rows == 0)
{
}
elseif($rows > 0)
{
while($row = mysql_fetch_array($query))
{
$person = htmlspecialchars($row['full_name']);
}
}
}
print $person;
Because your overwriting
$personon each iteration.Hold it in a
$person[]array if your expecting more then one. Then loop through it with a foreach loop when you intend to output.Not related but your also querying twice, you only need 1
$result = mysql_query($sql);
Update (Simple Outputting Example):
Or an alternative way to is to build your output within the loop using concatenation.
Or just echo it.