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Editorial Team
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Asked: 2026-05-28T16:32:10+00:00

The question almost says it all… So. im using jQuery’s drag and drop stuff,

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The question almost says it all…

So. im using jQuery’s drag and drop stuff, and I have the following problem.

I have a div #one and it can be dragged and then dropped into the div #two. Evereything works okay for now.

The thing is, that I want to save the position, where the #one was dropped. I get the position of #one with .position() – after dropping, I call .position() and the problem is that it calculates it’s position relative to it’s parent div (wrapper).

I want the script to calculate the position of #one relative to the #two (div where I dropped #one).

I cheated a bit, created #one immidiately in #two, and set it’s left and top properties to -120px and 0px, so that the div would show outside #two, and when I dragged then #one into #two, I would get proper position.. But I don’t want to do this like that..

Is there a way to find absolute position on #one relative to the #two after it was dropped in it ?

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1 Answer

  1. Editorial Team

    If I understood correctly, You want to find position (left,top) of #one w.r.t #two. If so, you can use .offset function to find the position of #two and #one and subtract their position to get the relative position of the #one inside #two.

    DEMO here

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