Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7594381
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 30, 20262026-05-30T21:24:07+00:00 2026-05-30T21:24:07+00:00

The question at strlen in assembly is about strlen in assembly, but that seems

  • 0

The question at strlen in assembly
is about strlen in assembly, but that seems to be written in AT&T syntax, which unfortunately isn’t supported by my assembler.

I’m just curious how would you translate the syntax [eax + ebx] to the intel’s syntax?

So

4(%eax)     # offset 4

is equivalent to

[eax + 4]

Suppose the offset value is stored in %ebx.
What’s the equivalence of

[eax + ebx]

?

%ebx(%eax)     # doesn't work!

Thanks,

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-30T21:24:09+00:00Added an answer on May 30, 2026 at 9:24 pm

    [eax+ebx] should be translated to (%eax,%ebx).

    The full syntax for memory addresses in AT&T syntax is:

    offset(%reg1,%reg2,scale)
    

    which is equivalent to:

    [reg1 + reg2*scale + offset]
    

    offset and scale are constant values, and scale must be 1, 2, 4, or 8. Defaults are 0 for offset and 1 for scale.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

This seems like a basic question but i have doubts maybe because i am
Question Can I build a image database/library that has an e-commerce style checkout system
Question says it all, really. My application is a time tracker. It's currently written
It's a simple question, but the solution appears to be far from simple. I
I tried to search the site for this question but didn't find this exactly,
This is a very small question, and probably something really silly! But why am
So I started a question to figure out why my PHP code that is
This is probably a naive question but, how do I get the length of
Stupid question. I've got a project that I'm working on in PHP; it's a
I have a question about arrays and foreach. If i have an array like

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.