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Asked: 2026-05-27T19:50:36+00:00

The question is: How can I order by a sql statement using an if

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The question is: “How can I order by a sql statement using an if value?”

I have a table in which I have a parameters and using this parameters I have to order by ASC or DESC a single column. How can I achieve it?

I have understood that the ASC and DESC parameters cannot be in a IF block (and have a structure like this one. “IF(Type = ‘1’, ranking, ranking) ASC/DESC”), so which is the alternative to order inside a select in base to a parameters?

EXAMPLE

The table is something like:

ID | RANKING | TYPE
--------------------
1 | 12 | 1
2 | 10 | 1
3 | 14 | 2
4 | 15 | 2

The Type = 1 have to be an ASC order and the Type = 2 have to be a DESC order, so the expected result of my SELECT could be:

ID | RANKING | TYPE
--------------------
2 | 10 | 1
1 | 12 | 1
4 | 15 | 2
3 | 14 | 2

Any idea about it?

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1 Answer

  1. Editorial Team

    How about ordering by IF(type=2, -ranking, ranking) after ordering by type? Negating the ranking will cause the opposite order for that type.

    EDIT

    Since ranking is a VARCHAR column, you would need to to convert it to a number to use this technique.

    SELECT * FROM test ORDER BY type ASC, CAST(ranking as SIGNED)*IF(type = 1, 1, -1) ASC;

    You can test the code directly at sqlfiddle

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