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Home/ Questions/Q 4027266
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T11:04:32+00:00 2026-05-20T11:04:32+00:00

The question is simple: what is lifetime of that functor object that is automatically

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The question is simple: what is lifetime of that functor object that is automatically generated for me by the C++ compiler when I write a lambda-expression?

I did a quick search, but couldn’t find a satisfactory answer. In particular, if I pass the lambda somewhere, and it gets remembered there, and then I go out of scope, what’s going to happen once my lambda is called later and tries to access my stack-allocated, but no longer alive, captured variables? Or does the compiler prevent such situation in some way? Or what?

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  1. Editorial Team
    Editorial Team
    2026-05-20T11:04:32+00:00Added an answer on May 20, 2026 at 11:04 am

    Depends on how you capture your variables. If you capture them by reference ([&]) and they go out of scope, the references will be invalid, just like normal references. Capture them by value ([=]) if you want to make sure they outlife their scope.

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