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Home/ Questions/Q 6348909
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T21:30:46+00:00 2026-05-24T21:30:46+00:00

The Rails I18n library transforms a YAML file into a data structure that is

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The Rails I18n library transforms a YAML file into a data structure that is accessible via a dotted path call using the t() function.

t('one.two.three.four')

Does anyone know how to do this with a Ruby Hash? Or is it only possible directly via a YAML object?

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  1. Editorial Team
    Editorial Team
    2026-05-24T21:30:46+00:00Added an answer on May 24, 2026 at 9:30 pm

    Just split on a dot in the path and iterate over this to find the right hash?

    path.split(".").inject(hash) { |hash, key| hash[key] }
    

    Alternatively you can build a new hash by iterating recursively over the whole structure:

    def convert_hash(hash, path = "")
      hash.each_with_object({}) do |(k, v), ret|
        key = path + k
    
        if v.is_a? Hash
          ret.merge! convert_hash(v, key + ".")
        else
          ret[key] = v
        end
      end
    end
    
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