Question

The response of my request is a java script code. When I put the url in browser, I can see the whole generated java script code on the page. Format of url passed to $.ajax is as below:

http://localhost:8080/vi-api/viapi?action=tag&projectId=45&tagId=345

When I put the above URL I can see the request is successful. Now, I am using below Ajax request for this url using jQuery.

   var finalUrl = "http://localhost:8080/vi-api/viapi?action=tag&projectId=45&tagId=345";
   var req = $.ajax({
             type:"GET",
             url:finalUrl,
             type:"script",
             data:"",
             success: function(html){
                alert('Requese sucessful.');
              },
            complete:function(jqXHR, textStatus) {
                alert("request complete "+textStatus);
             },
            error: function(xhr, textStatus, errorThrown){
                alert('request failed->'+textStatus);
            }             
           });  

Question 1:This gives the alert “request failed error’. Why this is so ?

Question 2:Is there any way to return success/failure code in above process?

Answer 1

In:

$.ajax({
     type:"GET",
     url:finalUrl,
     type:"script",
     (...)

You have two times the ‘type’ key in your object. So I think only the second one is taken (‘script’). Obviously ‘script’ is not a valid HTTP method (as HEAD,GET,PUT,POST, etc). The keyword your were looking at for ‘script’ is maybe dataType which may be one of xml, json, jsonp, text, script, or html.

Do not forget to look at jsonp, it’s usually a nice way to return a script content and to call it.