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Home/ Questions/Q 8792063
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T22:55:41+00:00 2026-06-13T22:55:41+00:00

The sample code is:- import javax.sound.midi.*; import java.io.*; class test{ public void go() throws

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The sample code is:-

import javax.sound.midi.*;
import java.io.*;

class test{

public void go() throws MidiUnavailableException{
//try{
Sequencer sequencer = MidiSystem.getSequencer();
System.out.println("Got it");
//}

/*catch(Exception ex){
System.out.println("Size Matters");
}*/

/*catch(MidiUnavailableException ex){
System.out.println("I am the incorrect exception");
}*/
}

public static void main(String [] args) throws MidiUnavailableException{
test obj = new test();
//try{
obj.go();
//}
/*catch(MidiUnavailableException mex){
System.out.println("Compiler should catch me");

}*/

}
}

I don’t get any while compiling the code; does that mean that JVM will handle the exception in the case? Or if the system is not able to give a sequencer then my program will terminate?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T22:55:41+00:00Added an answer on June 13, 2026 at 10:55 pm

    Yes. An unhandled exception will kill the thread. When all non-daemon threads terminate your program will terminate. The exit status is non-zero if the last thread terminated with an exception. And your program has only one thread.

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