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Home/ Questions/Q 7404771
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T05:18:13+00:00 2026-05-29T05:18:13+00:00

The scala code is simple: case class X(id: Option[String] = None, username: Option[String]) object

  • 0

The scala code is simple:

case class X(id: Option[String] = None, username: Option[String])

object X {
  def create(x: X): X = {
    x.copy(id = Some("111"))
  }
}

class Test {

  def test() {
    val x = X.create(X(
      username = Some("Hello, world!")))

    val id = x.id.get  // !!! reports: recursive value x needs type
  }

}

Please note the line:

 val id = x.id.get

Why it reports recursive value x needs type?

If I change the variable name, as:

val dd = x.id.get

It will be OK.

PS: scala version is: 2.9.1.final

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T05:18:14+00:00Added an answer on May 29, 2026 at 5:18 am

    Removing the default argument for id in the definition of case class X also fixes the problem which suggests that this is an instance of SI-5091.

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