Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
The sed manual clearly states that the available backreferences available for the replacement string in a substitute are numbered \1 through \9. I’m trying to parse a log file that has 10 fields.
I have the regex formed for it but the tenth match (and anything after) isn’t accessible.
Does anyone have an elegant way to circumvent this limitation in KSH (or any language that perhaps I can port to shell scripting)?
Can you user
perl -pe 's/(match)(str)/$2$1/g;'in place of sed? The way to circumvent the backreference limit is to use something other than sed.Also, I suppose you could do your substitution in two steps, but I don’t know your pattern so I can’t help you out with how.