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Home/ Questions/Q 246129
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T21:08:48+00:00 2026-05-11T21:08:48+00:00

The situation: index.php: <?php include(foo.php); include(baz.php); foo(bar.php); ?> baz.php: <?php $x = 42; ?>

  • 0

The situation:

index.php:

<?php
    include("foo.php");
    include("baz.php");
        foo("bar.php");
?>

baz.php:

<?php
    $x = 42;
?>

foo.php:

<?php
    function foo($p) {
        include_once($p); // please dont mind the inclusion hole
    }
?>

bar.php:

<?php
    echo $x;
?>

Zend notice: Undefined variable: x

Placing global $x; in bar.php removes the notice, but I understand why there is a notice about this in the first place.. Doesn’t include pretty much work like including C headers? It would mean that the interpreted code would look like this:

<?php
    function foo($p) {
        include_once($p); // please dont mind the inclusion hole
    }
    $x = 42;

    // this however, is included by a function...
    // does the function's scope influence the stuff it includes?
    echo $x; // undefined variable
?>

My editor is the Eclipse/Zend package.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T21:08:48+00:00Added an answer on May 11, 2026 at 9:08 pm

    I’m no expert, so please don’t flame me if I’m wrong, but I think the file called by include_once or require_once is called in the context of the caller. Since function foo() won’t know about $x then neither will any of its called includes. You could experiment by ‘declaring’ $x inside function foo() with the same setup as above.

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