Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 1838330
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 17, 20262026-05-17T06:27:49+00:00 2026-05-17T06:27:49+00:00

The standard C library functions strtof and strtod have the following signatures: float strtof(const

  • 0

The standard C library functions strtof and strtod have the following signatures:

float strtof(const char *str, char **endptr);
double strtod(const char *str, char **endptr); 

They each decompose the input string, str, into three parts:

  1. An initial, possibly-empty, sequence of whitespace
  2. A “subject sequence” of characters that represent a floating-point value
  3. A “trailing sequence” of characters that are unrecognized (and which do not affect the conversion).

If endptr is not NULL, then *endptr is set to a pointer to the character immediately following the last character that was part of the conversion (in other words, the start of the trailing sequence).

I am wondering: why is endptr, then, a pointer to a non-const char pointer? Isn’t *endptr a pointer into a const char string (the input string str)?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-17T06:27:50+00:00Added an answer on May 17, 2026 at 6:27 am

    The reason is simply usability. char * can automatically convert to const char *, but char ** cannot automatically convert to const char **, and the actual type of the pointer (whose address gets passed) used by the calling function is much more likely to be char * than const char *. The reason this automatic conversion is not possible is that there is a non-obvious way it can be used to remove the const qualification through several steps, where each step looks perfectly valid and correct in and of itself. Steve Jessop has provided an example in the comments:

    if you could automatically convert char** to const char**, then you could do

    char *p;
    char **pp = &p;
    const char** cp = pp;
    *cp = (const char*) "hello";
    *p = 'j';.
    

    For const-safety, one of those lines must be illegal, and since the others are all perfectly normal operations, it has to be cp = pp;

    A much better approach would have been to define these functions to take void * in place of char **. Both char ** and const char ** can automatically convert to void *. (The stricken text was actually a very bad idea; not only does it prevent any type checking, but C actually forbids objects of type char * and const char * to alias.) Alternatively, these functions could have taken a ptrdiff_t * or size_t * argument in which to store the offset of the end, rather than a pointer to it. This is often more useful anyway.

    If you like the latter approach, feel free to write such a wrapper around the standard library functions and call your wrapper, so as to keep the rest of your code const-clean and cast-free.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have the following problem that the standard library doesn't solve well, and I'm
While searching for some functions in C++ standard library documentation I read that push
The strchr function in the C standard library looks for a char in a
This question is about the specification of several functions in the C++11 Standard Library,
There are many endearing string functions in the C standard library, such as (in
If for example I should not use standard library functions like printf() , putchar()
I'm currently working with php standard library functions to sanitize string inputs for mysql_query
Buffer overrun problems are well known. Thus we were blessed with standard library functions
I know standard c library functions fwrite and fread are a sort buffering wrappers
I have a linked list structure: struct SomeLinkedList { const char* bar; int lots_of_interesting_stuff_in_here;

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.