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Home/ Questions/Q 6081989
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T11:14:19+00:00 2026-05-23T11:14:19+00:00

The standard says that std::binary_search(…) and the two related functions std::lower_bound(…) and std::upper_bound(…) are

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The standard says that std::binary_search(...) and the two related functions std::lower_bound(...) and std::upper_bound(...) are O(log n) if the data structure has random access. So, given that, I presume that these algorithms have O(log n) performance on std::deque (assuming its contents are kept sorted by the user).

However, it seems that the internal representation of std::deque is tricky (it’s broken into chunks), so I was wondering: does the requirement of O(log n) search hold for std::deque.

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  1. Editorial Team
    Editorial Team
    2026-05-23T11:14:19+00:00Added an answer on May 23, 2026 at 11:14 am

    Yes it still holds for deque because the container is required to provide access to any element in constant time (just a slightly higher constant than vector).

    That doesn’t relieve you of the obligation for the deque to be sorted though.

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