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Home/ Questions/Q 7526995
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T03:59:28+00:00 2026-05-30T03:59:28+00:00

The string, when displayed looks like: value1, value2, value3, value4, value5 etc.. What I

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The string, when displayed looks like: value1, value2, value3, value4, value5 etc..

What I want the string to do once I display it is (removing spaces and commas, i assume I can use index + 2 or something to get past the comma):

value1

value2

etc…

lastKnownIndexPos = 0;

foreach (System.Text.RegularExpressions.Match m in System.Text.RegularExpressions.Regex.Matches(unformatedList, ",?")) //Currently is ',' can I use ', '?
{
    list += unformatedList.Substring(lastKnownIndexPos, m.Index - 1) + "\n\n"; //-1 to grab just the first value.

    lastIndex = m.Index + 2; //to skip the comma and the space to get to the first letter of the next word.

    //lastIndex++; //used this to count how many times it was found, maxed at 17 (have over 100):(
}

//MessageBox.Show(Convert.ToString(lastIndex)); //used to display total times each was found.

MessageBox.Show(list);

At the moment the message box does not show any text, but using the lastIndex I get a value of 17 so I know it works for part of it 😛

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  1. Editorial Team
    Editorial Team
    2026-05-30T03:59:30+00:00Added an answer on May 30, 2026 at 3:59 am

    That’s easy (I’m using System.Linq here):

    var formatted = string.Join("\n\n", unformatedList.Split(',').Select(x => x.Trim()));
    MessageBox.Show(formatted);
    

    An alternative approach, as swannee pointed out, would be the following:

    var formatted = Regex.Replace(unformatedList, @"\s*,\s*", "\n\n").Trim();
    

    Edit:
    To make the above examples work regardless of how you use the result string, you should use Environment.NewLine instead of "\n".

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